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Proof step 1 from proof cast-mult-neg (conclusion)

⊦ j < 0 ∧ j0 < 0 ∧ 0 < i → cast(i, j * 2 ^ i + j0) = cast(i, j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j < 0, j0 < 0, 0 < i ⊦ cast(i, j * 2 ^ i + j0) = cast(i, j0)

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)