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Proof step 1 from proof cast-mult-pos (conclusion)

⊦ 0 ≤ j ∧ 0 ≤ j0 ∧ 0 < i → cast(i, j * 2 ^ i + j0) = cast(i, j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ j, 0 ≤ j0, 0 < i ⊦ cast(i, j * 2 ^ i + j0) = cast(i, j0)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)