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Proof step 1 from proof cast-neg-add-01 (conclusion)

⊦ 0 < i → cast(i, cast(i, ~ j) + j0) = cast(i, ~ cast(i, j) + j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ cast(i, cast(i, ~ j) + j0) = cast(i, j0 - cast(i, j))

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + ~ j = i - j;