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Proof step 1 from proof cast-neg-add (conclusion)

⊦ 0 < i → cast(i, cast(i, ~ j) + j0) = cast(i, ~ j + j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
0 < i ⊦ cast(i, j + j0) = cast(i, cast(i, j) + j0)

Rule argument

name: cast-law-add-one rotate: F subst: [j0, j, i] → [j0, ~ j, i]

Additional information

Used simplifier rules: ⊦ i + j = j + i; Used terms: j0, ~ j, i