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Proof step 5 from proof cast-one (previous step)

⊦ bits2int(fillsgn(1, int2bits(j)).last ') = 0, bits2int(fillsgn(1, int2bits(j)).last ') = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 7:
1 ≤ # int2bits(j) ⊦ bits2int(int2bits(j).last ') = 0, bits2int(int2bits(j).last ') = ~1

Rule argument

seq: ⊦ n ≤ # bits → fillsgn(n, bits) = bits subst: [bits, n] → [int2bits(j), 1] rotate: F spec: bitopsaux inst: name: fillsgn-longer

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < 1 ↔ m = 0;% ⊦ # bits = 0 ↔ bits = [];% ⊦ int2bits(j) ≠ []; Used terms: int2bits(j), 1