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Proof step 3 from proof cast-sub-2pot (previous step)

2 ^ i - j0 = 1 * 2 ^ i + ~ j0, 0 < i ⊦ cast(i, 2 ^ i - j0) = cast(i, ~ j0)

User applied rule insert equation

And obtained the following new goals

Proof step 4:
0 < i ⊦ cast(i, 1 * 2 ^ i + ~ j0) = cast(i, ~ j0)

Rule argument

pos: left 1 flags: discard

Additional information