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Proof step 22 from proof divide-by-10 (previous step)

0 ≤ j, 0 ≤ i0, j < 10, i0 * 10 + j ≤ 65536, 0 ≤ 52429 * j + 2 * i0 ⊦ (52429 * j + 2 * i0) / 524288 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
0 < j, 0 ≤ i, i < j ⊦ i / j = 0
Proof step 24:
¬(0 < 524288 ∧ 0 ≤ 52429 * j + 2 * i0 ∧ 52429 * j + 2 * i0 < 524288), 0 ≤ j, 0 ≤ i0, j < 10, i0 * 10 + j ≤ 65536, 0 ≤ 52429 * j + 2 * i0 ⊦ (52429 * j + 2 * i0) / 524288 = 0

Rule argument

spec: int-div inst: name: div-zero seq: 0 < j, 0 ≤ i, i < j ⊦ i / j = 0 subst: [j, i] → [524288, 52429 * j + 2 * i0] flags: rewrite

Additional information

Used terms: 524288, 52429 * j + 2 * i0