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Proof step 22 from proof intshiftleft-is-mult-01 (previous step)

¬(0 ≤ j ∧ ¬ false ∈ int2bits(31).rest ∧ 0 ≤ 31), 0 ≤ j, i < 0 ⊦ (i + 1) * 2 ^ abs(band(j, 31)) = 2 ^ abs(band(j, 31)) + i * 2 ^ band(j, 31), band(j, 31) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
0 ≤ j, i < 0, false ∈ int2bits(31).rest ⊦ (i + 1) * 2 ^ abs(band(j, 31)) = 2 ^ abs(band(j, 31)) + i * 2 ^ band(j, 31), band(j, 31) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;