[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 26 from proof intshiftleft-is-mult-01 (previous step)

0 ≤ j, i < 0 ⊦ 2 ^ abs(j % 32) * (i + 1) = 2 ^ (j % 32) * i + 2 ^ abs(j % 32), j % 32 = 0, false ∈ int2bits(31).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ j ≠ 0 → abs(i % j) = abs(i) % abs(j)

Rule argument

seq: ⊦ j ≠ 0 → abs(i % j) = abs(i) % abs(j) subst: [j, i] → [32, j] rotate: F spec: int-div inst: name: abs-shift

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ 0 ≤ i → abs(i) = i;% ⊦ i * j + i = i * (j + 1);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i + j + i0 = (i + j) + i0; Used terms: 32, j