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Proof step 46 from proof intshiftleft-is-mult-01 (previous step)

j < 0 ∧ ¬ false ∈ int2bits(31).rest ∧ 0 ≤ 31, 0 < i, j < 0 ⊦ (j + 1) % (31 + 1) + 31 = 0, i = 0, 2 ^ abs((j + 1) % (31 + 1) + 31) = 2 ^ ((j + 1) % (31 + 1) + 31)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 47:
0 < i, j < 0 ⊦ ~31 = (j + 1) % 32, i = 0, 2 ^ abs(31 + (j + 1) % 32) = 2 ^ (31 + (j + 1) % 32), false ∈ int2bits(31).rest

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;