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Proof step 5 from proof intshiftleft-is-mult-01 (previous step)

¬(# mklist(false, i→n(band(j, 31))) ≠ 0 ∧ # int2bits(i) ≠ 0 ∧ ¬ int2bits(i).first) ⊦ bits2int(int2bits(i) + mklist(false, i→n(band(j, 31)))) = i * 2 ^ band(j, 31)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j).first ↔ j < 0;% ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ # mklist(boolvar, n) = n;