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Proof step 52 from proof intshiftleft-is-mult-01 (previous step)

0 ≤ j ∧ ¬ false ∈ int2bits(31).rest ∧ 0 ≤ 31, 0 < i ⊦ j % (31 + 1) = 0, i = 0, 2 ^ abs(j % (31 + 1)) = 2 ^ (j % (31 + 1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 53:
0 < i, 0 ≤ j ⊦ j % 32 = 0, i = 0, 2 ^ abs(j % 32) = 2 ^ (j % 32), false ∈ int2bits(31).rest

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)