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Proof step 1 from proof intshiftright-ls-01 (conclusion)

⊦ 0 ≤ j ∧ j < 32 → (i i>> j < 0 ↔ i < 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j < 32, 0 ≤ j ⊦ i i>> j < 0 ↔ ¬ 0 ≤ i

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;