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Proof step 13 from proof intshiftright-ls-01 (previous step)

mklist(i < 0, i→n(j)) + int2bits(i) ≠ [] ∧ # int2bits(i) ≠ 0, j < 32, 0 ≤ j ⊦ bits2int((mklist(i < 0, i→n(j)) + int2bits(i)).first ' + sublist(0, (# int2bits(i))-1, (mklist(i < 0, i→n(j)) + int2bits(i)).rest)) < 0 ↔ ¬ 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
j < 32, 0 ≤ j ⊦ bits2int((mklist(i < 0, i→n(j)) + int2bits(i)).first ' + sublist(0, # int2bits(i) - 1, (mklist(i < 0, i→n(j)) + int2bits(i)).rest)) < 0 ↔ ¬ 0 ≤ i, mklist(¬ 0 ≤ i, i→n(j)) + int2bits(i) = []

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ n -1 = n - 1;