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Proof step 4 from proof intshiftright-ls-01 (previous step)

j < 32, 0 ≤ j ⊦ bits2int(sublist(0, # int2bits(i), mklist(int2bits(i).first, i→n(band(j, 31))) + int2bits(i))) < 0 ↔ ¬ 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
j < 32, 0 ≤ j ⊦ bits2int(sublist(0, # int2bits(i), mklist(i < 0, i→n(band(j, 31))) + int2bits(i))) < 0 ↔ ¬ 0 ≤ i

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j).first ↔ j < 0;