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Proof step 11 from proof intshiftrsign-2pot-neg-01 (previous step)

0 < j, abs(j1) < 2, i0 < j, i0 ≤ 0, j1 < j, j1 ≤ 0, j < 32, i0 * 2 + j1 < ~1, i0 * 2 + j1 < 0, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = (i - (2 ^ j0 - 1)) / 2 ^ j0 ⊦ j = 1, (i0 + 1 - 2 ^ (j - 1)) / 2 ^ (j - 1) = (2 * (i0 + 1) + j1 - 2 ^ j) / 2 ^ j

User applied rule cut formula

And obtained the following new goals

Proof step 12:
j1 = ~1, 0 < j, abs(j1) < 2, i0 < j, i0 ≤ 0, j1 < j, j1 ≤ 0, j < 32, i0 * 2 + j1 < ~1, i0 * 2 + j1 < 0, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = (i - (2 ^ j0 - 1)) / 2 ^ j0 ⊦ j = 1, (i0 + 1 - 2 ^ (j - 1)) / 2 ^ (j - 1) = (2 * (i0 + 1) + j1 - 2 ^ j) / 2 ^ j
Proof step 29:
0 < j, abs(j1) < 2, i0 < j, i0 ≤ 0, j1 < j, j1 ≤ 0, j < 32, i0 * 2 + j1 < ~1, i0 * 2 + j1 < 0, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = (i - (2 ^ j0 - 1)) / 2 ^ j0 ⊦ j1 = ~1, j = 1, (i0 + 1 - 2 ^ (j - 1)) / 2 ^ (j - 1) = (2 * (i0 + 1) + j1 - 2 ^ j) / 2 ^ j

Rule argument

fma: j1 = ~1

Additional information

Used formulas: j1 = ~1