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Proof step 25 from proof intshiftrsign-2pot-neg-01 (previous step)

2 ^ (j - 1) = 0, i0 < 0, 0 ≤ j, j < 32, 0 < j, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = (i - (2 ^ j0 - 1)) / 2 ^ j0 ⊦ j = 1, (1 + i0) / 0 = ((i0 + 1) * 2 - 1) / 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 26:
⊦ 0 ≤ j → 2 ^ j ≠ 0

Rule argument

seq: ⊦ 0 ≤ j → 2 ^ j ≠ 0 subst: [j] → [j - 1] rotate: F spec: int-pot inst: name: two-zero

Additional information

Used simplifier rules: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i ≤ j → (j ≤ i ↔ i = j); Used terms: j - 1