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Proof step 37 from proof intshiftrsign-2pot-neg-01 (previous step)

¬ 2 ^ (j - 1) ≠ 0, j < 32, i0 < j, 0 < j, i0 < 0, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = (i - (2 ^ j0 - 1)) / 2 ^ j0 ⊦ j = 1, (i0 + 1 - 2 ^ (j - 1)) / 2 ^ (j - 1) = (2 * (i0 + 1 - 2 ^ (j - 1))) / (2 * 2 ^ (j - 1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
2 ^ (j - 1) = 0, i0 < 0, 0 < j, i0 < j, j < 32, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = (i - (2 ^ j0 - 1)) / 2 ^ j0 ⊦ j = 1, (1 + i0) / 0 = (2 * (1 + i0)) / 0

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* i) + i0 - (* j) = (i - j) + i0;