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Proof step 30 from proof intshiftrsign-2pot-neg (previous step)

2 ^ (j - 1) = 0, 0 i>> (j - 1) = 0 / 0, j0 * 2 ^ j < 0, j < 32, 0 < j, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ i % 2 ^ j0 = 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = i / 2 ^ j0 ⊦ 0 / 0 = j0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 31:
⊦ 0 < j → (i ^ j = 0 ↔ i = 0)

Rule argument

seq: ⊦ 0 < j → (i ^ j = 0 ↔ i = 0) subst: [j, i] → [j - 1, 2] rotate: F spec: int-pot inst: name: zero

Additional information

Used simplifier rules: ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ 0 < i → (i ≤ 1 ↔ i = 1);% ⊦ i = j → i - j = 0; Used terms: j - 1, 2