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Proof step 5 from proof intshiftrsign-2pot-neg (previous step)

i < 0 ∧ 0 < j ∧ j < 32, i % 2 ^ j = 0, j < 32, i < 0, 0 < j, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ i % 2 ^ j0 = 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = i / 2 ^ j0 ⊦ (i - 1) / 2 i>> (j - 1) = i / 2 ^ j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i % 2 ^ j = 0, 0 < j, i < 0, j < 32, ∀ i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ i % 2 ^ j0 = 0 ∧ 0 < j0 ∧ j0 < 32 → i i>> j0 = i / 2 ^ j0 ⊦ (i - 1) / 2 i>> (j - 1) = i / 2 ^ j

Proof step 5 from proof intshiftrsign-2pot-neg (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information