j < 32 ∧ 0 ≤ i ∧ 0 < j, ∀ i, j0. i→n(j0) < i→n(j) → j0 < 32 ∧ 0 ≤ i ∧ 0 < j0 → i i>> j0 = i / 2 ^ j0 ⊦ i i>> j = i / 2 ^ j
Used simplifier rules: <; (wellfounded) Used terms: i→n(j)