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Proof step 1 from proof intshiftrsign-if (conclusion)

⊦ i i>> j = (# int2bits(i) ≤ i→n(band(j, 31)) ⊃ (i < 0 ⊃ ~1;0);bits2int(sublist(0, # int2bits(i) - i→n(band(j, 31)), int2bits(i))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ i i>> j = (¬ i→n(band(j, 31)) < # int2bits(i) ⊃ (¬ 0 ≤ i ⊃ ~1;0);bits2int(sublist(0, # int2bits(i) - i→n(band(j, 31)), int2bits(i))))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ m ≤ n ↔ n < m;