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Proof step 8 from proof intshiftrsign-if (previous step)

¬ 0 ≤ i, # int2bits(i) ≤ i→n(band(j, 31)) ⊦ bits2int(sublist(0, # int2bits(i), mklist(¬ 0 ≤ i, i→n(band(j, 31))) + int2bits(i))) = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
# int2bits(i) ≤ i→n(band(j, 31)), i < 0 ⊦ bits2int(sublist(0, # int2bits(i), mklist(true, i→n(band(j, 31))) + int2bits(i))) = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;