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Proof step 1 from proof intshiftrsign-neg-02 (conclusion)

⊦ i < 0 ∧ i % 256 ≠ 0 → i i>> 8 = i / 256 - 1

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ i < 0 ∧ 0 < j ∧ j < 32 → i i>> j = (i - (2 ^ j - 1)) / 2 ^ j
Proof step 3:
i < 0 ∧ 0 < 8 ∧ 8 < 32 → i i>> 8 = (i - (2 ^ 8 - 1)) / 2 ^ 8 ⊦ i < 0 ∧ i % 256 ≠ 0 → i i>> 8 = i / 256 - 1

Rule argument

name: intshiftrsign-2pot-neg-01 subst: [i, j] → [i, 8]

Additional information

Used terms: i, 8