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Proof step 28 from proof intshiftrsign-rec-neg (previous step)

# int2bits((i - 1) / 2) + 1 ≠ 0, i < 0, j < 32, 0 < j ⊦ i = ~1, bits2int(true ' + sublist(0, (# int2bits((i - 1) / 2) + 1)-1, mklist(true, i→n(j) - 1) + int2bits((i - 1) / 2) + (i % 2 ≠ 0)')) = bits2int(sublist(0, # int2bits((i - 1) / 2), mklist(true, i→n(j - 1)) + int2bits((i - 1) / 2))), j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
i < 0, j < 32, 0 < j ⊦ j = 0, i = ~1, bits2int(true ' + sublist(0, # int2bits((i - 1) / 2), mklist(true, i→n(j) - 1) + int2bits((i - 1) / 2) + (i % 2 ≠ 0)')) = bits2int(sublist(0, # int2bits((i - 1) / 2), mklist(true, i→n(j - 1)) + int2bits((i - 1) / 2)))

Rule argument

Additional information

Used simplifier rules: ⊦ m + 1 ≠ 0;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ (m + 1)-1 = m;