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Proof step 42 from proof intshiftrsign-rec-neg (previous step)

i < 0, j < 32, 0 < j, sublist(0, # int2bits((i - 1) / 2), mklist(true, i→n(j) - 1) + int2bits((i - 1) / 2)).first ⊦ j = 0, i = ~1, bits2int(sublist(0, # int2bits((i - 1) / 2), mklist(true, i→n(j) - 1) + int2bits((i - 1) / 2))) = bits2int(sublist(0, # int2bits((i - 1) / 2), mklist(true, i→n(j - 1)) + int2bits((i - 1) / 2)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 43:
⊦ 1 < i → i→n(i - 1) = i→n(i) -1

Rule argument

seq: ⊦ 1 < i → i→n(i - 1) = i→n(i) -1 subst: [i] → [j] rotate: F spec: intnat inst: name: rax-01

Additional information

Used simplifier rules: ⊦ n -1 = n - 1;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ 0 < i → (i ≤ 1 ↔ i = 1);% ⊦ i = j → i - j = 0;% ⊦ mklist(boolvar, 0) = [];% ⊦ [] + bits = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ sublist(0, # bits, bits) = bits;% ⊦ bits2int(int2bits(i)) = i; Used terms: j