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Proof step 35 from proof intshiftrsign-rec-pos (previous step)

abs(i0) < 32, i0 < 31, 0 ≤ i, 0 ≤ i0, 1 < i, 0 < i ⊦ bits2int ( sublist(0, # int2bits(i / 2), (false ' + mklist(false, i→n(i0))) + int2bits(i / 2) + (i % 2 = 1)') + ((false ' + mklist(false, i→n(i0))) + int2bits(i / 2) + (i % 2 = 1)')[# int2bits(i / 2)] ') = bits2int(sublist(0, # int2bits(i / 2), mklist(false, i→n(i0)) + int2bits(i / 2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: j0 ≠ 0, j < j0 ⊦ i < (* j) → i < (* j0);% ⊦ 0 ≤ i → abs(i) = i;