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Proof step 48 from proof intshiftrsign-rec-pos (previous step)

i0 < 31, 0 ≤ i, 0 ≤ i0, 1 < i, 0 < i ⊦ bits2uint ( sublist(0, # int2bits(i / 2) - 1, mklist(false, i→n(i0)) + int2bits(i / 2)) + ((false ' + mklist(false, i→n(i0)) + int2bits(i / 2)) + (i % 2 = 1)')[# int2bits(i / 2)] ') = bits2int(sublist(0, # int2bits(i / 2), mklist(false, i→n(i0)) + int2bits(i / 2)))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [# int2bits(i / 2), m] rotate: T spec: nat inst: name: elim-pred-c

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ int2bits(j) ≠ [];%n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: # int2bits(i / 2), m