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Proof step 55 from proof intshiftrsign-rec-pos (previous step)

¬ ( ¬ (sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ').first ∧ sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ' ≠ []), # int2bits(i / 2) = m + 1, 0 < i, 1 < i, 0 ≤ i0, 0 ≤ i, i0 < 31 ⊦ bits2uint(sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ') = bits2int(sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
# int2bits(i / 2) = m + 1, 0 < i, 1 < i, 0 ≤ i0, 0 ≤ i, i0 < 31, (sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ').first ⊦ bits2uint(sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ') = bits2int(sublist(0, m, mklist(false, i→n(i0)) + int2bits(i / 2)) + (mklist(false, i→n(i0)) + int2bits(i / 2))[m] ')

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' ≠ [];% ⊦ sublist(0, n, bits) = [] ↔ n = 0;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];