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Proof step 62 from proof intshiftrsign-rec-pos (previous step)

# int2bits(i / 2) = 1, (mklist(false, i→n(i0)) + int2bits(i / 2)).first, 0 < i, 1 < i, 0 ≤ i0, 0 ≤ i, i0 < 31 ⊦ mklist(false, i→n(i0)) + int2bits(i / 2) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 63:
⊦ bits ≠ [] → ((bits + bits0).first ↔ bits.first)
Proof step 64:
mklist(false, i→n(i0)) ≠ [], # int2bits(i / 2) = 1, mklist(false, i→n(i0)).first, 0 < i, 1 < i, 0 ≤ i0, 0 ≤ i, i0 < 31 ⊦ mklist(false, i→n(i0)) + int2bits(i / 2) = []

Rule argument

seq: ⊦ bits ≠ [] → ((bits + bits0).first ↔ bits.first) subst: [bits0, bits] → [int2bits(i / 2), mklist(false, i→n(i0))] rotate: F spec: list inst: bitlista name: first-01

Additional information

Used simplifier rules: ⊦ mklist(boolvar, m) = [] ↔ m = 0;% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ mklist(boolvar, 0) = [];% ⊦ [] + bits = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ int2bits(j) ≠ [];% ⊦ int2bits(j).first ↔ j < 0;%0 < j ⊦ i / (* j) < 0 ↔ i + j ≤ 0;% ⊦ i + (* j) ≤ (* j0) ↔ i ≤ j0 - j;% ⊦ i < 0 ∧ 0 < j → ¬ j ≤ i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: int2bits(i / 2), mklist(false, i→n(i0))