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Proof step 6 from proof intshiftzero-mone (previous step)

~1 + 1 = 0 ⊦ bits2int(sublist(0, # fillsgn(32, true '), mklist(false, i→n(bits2int(bitsand(int2bits(16), int2bits(31))))) + fillsgn(32, true '))) = 65535

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ mklist(boolvar, 0) = [];%n ≠ 0 ⊦ mklist(true, (* n)) = true ' + mklist(true, n -1);% ⊦ 0 < n → fillsgn(n, boolvar ') = mklist(boolvar, n);