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Proof step 5 from proof longshiftright-2pot-pos (previous step)

j < 64, 0 ≤ i, 0 < j ⊦ i >> j = i / 2 ^ j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 ≤ i ∧ 0 ≤ j → i >> j = i / 2 ^ j

Rule argument

name: shiftright-pos-div rotate: F subst: [j, i] → [j, i]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ i < j → ¬ j < i; Used terms: j, i