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Proof step 3 from proof or-invandinv (previous step)

true, ∀ bits1, bits0. # bits1 < # bits → true → bits1 = [] ∨ bits0 = [] ∨ bitsor(bits1, bits0) = bitsinvert(bitsand(bitsinvert(bits1), bitsinvert(bits0))) ⊦ bits = [] ∨ bits0 = [] ∨ bitsor(bits, bits0) = bitsinvert(bitsand(bitsinvert(bits), bitsinvert(bits0)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ bits1, bits0. # bits1 < # bits → true → bits1 = [] ∨ bits0 = [] ∨ bitsor(bits1, bits0) = bitsinvert(bitsand(bitsinvert(bits1), bitsinvert(bits0))) ⊦ bitsor(bits, bits0) = bitsinvert(bitsand(bitsinvert(bits), bitsinvert(bits0))), bits0 = [], bits = []

Proof step 3 from proof or-invandinv (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information