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Proof step 1 from proof or-two (conclusion)

⊦ bitsor(boolvar ' + boolvar0 ', boolvar1 ' + boolvar2 ') = bitsor(boolvar ', boolvar1 ') + (boolvar0 ∨ boolvar2)

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ bitsor(bits + boolvar ' + boolvar0 ', bits0 + boolvar1 ' + boolvar2 ') = bitsor(bits + boolvar, bits0 + boolvar1) + (boolvar0 ∨ boolvar2)

Rule argument

name: bitsor-rec subst: [bits, boolvar, boolvar0, bits0, boolvar1, boolvar2] → [[], boolvar, boolvar0, [], boolvar1, boolvar2]

Additional information

Used simplifier rules: ⊦ [] + bits = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + boolvar = bits + boolvar '; Used terms: [], boolvar, boolvar0, [], boolvar1, boolvar2