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Proof step 11 from proof rightshift-zero (previous step)

i0 = i + 1, i0 >> 0 = i0 ⊦ i0 = (i >> 0) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
(i + 1) >> 0 = i + 1 ⊦ i = i >> 0

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = i + i0 ↔ j = i0;