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Proof step 7 from proof rightshift-zero (previous step)

⊦ (i0 + 1) >> 0 = i0 + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i >> j = bits2int(sublist(0, # int2bits(i), mklist(int2bits(i).first, i→n(j)) + int2bits(i)))

Rule argument

name: shiftrsign-01 rotate: F subst: [j, i] → [0, i0 + 1]

Additional information

Used simplifier rules: ⊦ int2bits(j).first ↔ j < 0;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ mklist(boolvar, 0) = [];% ⊦ [] + bits = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ sublist(0, # bits, bits) = bits;% ⊦ bits2int(int2bits(i)) = i;% ⊦ i + j = i + i0 ↔ j = i0; Used terms: 0, i0 + 1