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Proof step 4 from proof shiftright-abs (previous step)

⊦ bits2int(sublist(0, # int2bits(i), mklist(¬ 0 ≤ i, i→n(j)) + int2bits(i))) = i >> abs(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ i >> j = bits2int(sublist(0, # int2bits(i), mklist(int2bits(i).first, i→n(j)) + int2bits(i)))

Rule argument

name: shiftrsign-01 rotate: F subst: [j, i] → [abs(j), i]

Additional information

Used simplifier rules: ⊦ int2bits(j).first ↔ j < 0;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i→n(abs(i)) = i→n(i); Used terms: abs(j), i