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Proof step 3 from proof shiftright-minus-one (previous step)

⊦ bits2int(sublist(0, # int2bits(~1), mklist(int2bits(~1).first, i→n(j)) + int2bits(~1))) = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ bits2int(sublist(0, 1, mklist(true, i→n(j)) + true ')) = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar '.first ↔ boolvar;% ⊦ # boolvar ' = 0 +1;% ⊦ int2bits(~1) = true ';