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Proof step 7 from proof shiftright-minus-one (previous step)

⊦ bits2int(firstn(1, mklist(true, i→n(j)) + true ')) = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
n ≠ 0 ⊦ firstn((* n), bits) = bits.first ' + firstn(n -1, bits.rest)
Proof step 9:
1 ≠ 0 ⊦ bits2int((mklist(true, i→n(j)) + true ').first ' + firstn(1 -1, (mklist(true, i→n(j)) + true ').rest)) = ~1

Rule argument

seq: n ≠ 0 ⊦ firstn((* n), bits) = bits.first ' + firstn(n -1, bits.rest) subst: [bits, n] → [mklist(true, i→n(j)) + true ', 1] rotate: F spec: list-del inst: bitlista name: first-num

Additional information

Used terms: mklist(true, i→n(j)) + true ', 1