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Proof step 14 from proof shiftright-neg-mone (previous step)

i→n(j) < # int2bits(~1) ⊦ j = 0, bits2int(firstn(# int2bits(~1), mklist(true, i→n(j)) + int2bits(~1))) = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ i + 1 = 0 → int2bits(i) = true '

Rule argument

seq: ⊦ i + 1 = 0 → int2bits(i) = true ' subst: [i] → [~1] rotate: F spec: int2bits inst: name: int2bits-mone

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;% ⊦ m < 1 ↔ m = 0;% ⊦ i→n(i) = 0 ↔ i = 0; Used terms: ~1