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Proof step 5 from proof shiftright-neg-mone (previous step)

0 ≤ 2 ^ (abs(j) - 1) + i, i < 0 ⊦ bits2int(sublist(0, # int2bits(i), mklist(true, i→n(j)) + int2bits(i))) = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ sublist((* m), (* n), bits) = firstn(n, restn(m, bits))
Proof step 7:
0 ≤ 2 ^ (abs(j) - 1) + i, i < 0 ⊦ bits2int(firstn(# int2bits(i), restn(0, mklist(true, i→n(j)) + int2bits(i)))) = ~1

Rule argument

seq: ⊦ sublist((* m), (* n), bits) = firstn(n, restn(m, bits)) subst: [bits, n, m] → [mklist(true, i→n(j)) + int2bits(i), # int2bits(i), 0] rotate: F spec: list-del inst: bitlista name: sublist-num

Additional information

Used terms: mklist(true, i→n(j)) + int2bits(i), # int2bits(i), 0