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Proof step 4 from proof shiftright-not-le (previous step)

i ≤ i >> j, 0 < i, 0 < i >> j ⊦ i = 0, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 ≤ i ∧ j ≠ 0 → i >> j = i / 2 >> (abs(j) - 1)
Proof step 6:
0 ≤ i ∧ j ≠ 0, i ≤ i / 2 >> (abs(j) - 1), 0 < i, 0 < i / 2 >> (abs(j) - 1) ⊦ i = 0, j = 0

Rule argument

name: shiftright-rec-pos-01 rotate: F subst: [j, i] → [j, i]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: j, i