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Proof step 7 from proof shiftright-not-le (previous step)

i ≤ i / 2 >> (abs(j) - 1), 0 < i, 0 < i / 2 >> (abs(j) - 1) ⊦ i = 0, j = 0

User applied rule insert lemma

And obtained the following new goals

Rule argument

name: shiftright-not-ls-01 subst: [i, j] → [i / 2, abs(j) - 1]

Additional information

Used simplifier rules: ⊦ 0 ≤ i / 2 ↔ ~1 ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)% ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ 0 < i → ¬ i ≤ i / 2; Used terms: i / 2, abs(j) - 1