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Proof step 4 from proof shiftright-not-neg (previous step)

0 ≤ i, 0 ≤ i, i / 2 ^ abs(j) < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i / 2 ^ abs(j) < 0, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)