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Proof step 13 from proof shiftright-not-pos-01 (previous step)

# int2bits(i) ≠ 0 ∧ mklist(true, i→n(j)) + int2bits(i) ≠ [], i < 0 ⊦ (mklist(true, i→n(j)) + int2bits(i)).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
i < 0 ⊦ mklist(true, i→n(j)) + int2bits(i) = [], (mklist(true, i→n(j)) + int2bits(i)).first

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];