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Proof step 4 from proof shiftright-not-pos-01 (previous step)

i < 0, 0 ≤ bits2int(sublist(0, # int2bits(i), mklist(int2bits(i).first, i→n(j)) + int2bits(i))) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ bits2int(sublist(0, # int2bits(i), mklist(true, i→n(j)) + int2bits(i))), i < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ j < 0 → int2bits(j).first;