[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 100 from proof shiftright-rec-8-neg (previous step)

j0 * 256 >> (j - 1) = j0 >> (j - 9), 8 < j, 0 < j, j0 < 0, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 0, (1 + 512 * j0) / 512 = 1 + j0, (1 + 512 * j0) % 256 = 0, j = 8, j0 >> (j - 9) = ((1 + 512 * j0) / 512 - 1) >> (j - 9)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 101:
⊦ i + j = j + i
Proof step 102:
j0 * 256 >> (j - 1) = j0 >> (j - 9), 8 < j, 0 < j, j0 < 0, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 0, (512 * j0 + 1) / 512 = 1 + j0, (512 * j0 + 1) % 256 = 0, j = 8, j0 >> (j - 9) = ((512 * j0 + 1) / 512 - 1) >> (j - 9)

Rule argument

seq: ⊦ i + j = j + i subst: [j, i] → [512 * j0, 1] rotate: F spec: int-basic2 inst: name: add-c

Additional information

Used terms: 512 * j0, 1