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Proof step 109 from proof shiftright-rec-8-neg (previous step)

(i / 256 - 2) / 2 = (i / 256) / 2 - 1, (i - 1) / 2 >> (j - 1) = (((i - 1) / 2) / 256 - 1) >> (j - 9), 8 < j, i < 0, 0 < j, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 0, (i - 1) / 2 >> (j - 1) = (i / 256 - 2) / 2 >> (j - 9), ((i - 1) / 2) % 256 = 0, j = 8, i % 256 = 0, ((i - 1) / 2) / 256 = (i / 256 - 2) / 2 + 1

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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