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Proof step 11 from proof shiftright-rec-8-neg (previous step)

~(2 ^ (abs(8) - 1)) ≤ i ∧ i < 0, i < 0, ~128 ≤ i, ∀ i, j0. i→n(j0) < i→n(8) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ ~1 = (i - 255) / 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i < 0, ~128 ≤ i, ∀ i, j0. i→n(j0) < i→n(8) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ ~1 = (i - 255) / 256

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;