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Proof step 119 from proof shiftright-rec-8-neg (previous step)

256 ≠ 0 ∧ 2 ≠ 0, j0 >> (j - 1) = (j0 / 256 - 1) >> (j - 9), 0 < j, 8 < j, j0 < 0, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 0, j0 >> (j - 1) = ((j0 * 2) / (256 * 2) - 1) >> (j - 9), j0 % 256 = 0, j = 8, (j0 * 2) % 256 = 0, j0 / 256 = (j0 * 2) / (256 * 2)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;%j % j0 = 0, j ≠ 0, j0 ≠ 0 ⊦ (i * (* j0)) / (* j) = i / j / j0;